x^2+3x=62

Solution for x^2+3x=62 equation:

x^2+3x=62

We move all terms to the left:

x^2+3x-(62)=0

a = 1; b = 3; c = -62;
Δ = b2-4ac
Δ = 32-4·1·(-62)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{257}}{2*1}=\frac{-3-\sqrt{257}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{257}}{2*1}=\frac{-3+\sqrt{257}}{2}
$